1/2((3x^(2)-7x))=6

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Solution for 1/2((3x^(2)-7x))=6 equation: 


x in (-oo:+oo)

(1/2)*(3*x^2-(7*x)) = 6 // - 6

(1/2)*(3*x^2-(7*x))-6 = 0

(1/2)*(3*x^2-7*x)-6 = 0

1/2*(3*x^2-7*x)-6 = 0

1/2*(3*x^2-7*x)-6 = 0

3/2*x^2-7/2*x-6 = 0

3/2*x^2-7/2*x-6 = 0

3/2*x^2-7/2*x-6 = 0

DELTA = (-7/2)^2-(-6*3/2*4)

DELTA = 193/4

DELTA > 0

x = ((193/4)^(1/2)+7/2)/(3/2*2) or x = (7/2-(193/4)^(1/2))/(3/2*2)

x = ((193/4)^(1/2)+7/2)/3 or x = (7/2-(193/4)^(1/2))/3

(x-((7/2-(193/4)^(1/2))/3))*(x-(((193/4)^(1/2)+7/2)/3)) = 0

(x-((7/2-(193/4)^(1/2))/3))*(x-(((193/4)^(1/2)+7/2)/3)) = 0

( x-(((193/4)^(1/2)+7/2)/3) )

x-(((193/4)^(1/2)+7/2)/3) = 0 // + ((193/4)^(1/2)+7/2)/3

x = ((193/4)^(1/2)+7/2)/3

( x-((7/2-(193/4)^(1/2))/3) )

x-((7/2-(193/4)^(1/2))/3) = 0 // + (7/2-(193/4)^(1/2))/3

x = (7/2-(193/4)^(1/2))/3

x in { ((193/4)^(1/2)+7/2)/3, (7/2-(193/4)^(1/2))/3 }

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